X^2+3x+20=-2x^2

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Solution for X^2+3x+20=-2x^2 equation: 



X^2+3X+20=-2X^2

We move all terms to the left:

X^2+3X+20-(-2X^2)=0

We get rid of parentheses

X^2+2X^2+3X+20=0

We add all the numbers together, and all the variables

3X^2+3X+20=0

a = 3; b = 3; c = +20;
Δ = b2-4ac
Δ = 32-4·3·20
Δ = -231
Delta is less than zero, so there is no solution for the equation

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